| 76. 
Since k>1 the first series will be alternating signs.
If k>3 the second series will converge (r=3/4 - geometric).
So both series will converge for k=3. |
Answer D |
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| 77. 
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Answer E |
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| 78.
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Answer B |
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| 79. 
If a=1 there is a hole in the function.
If a = 4 there is a hole in the function
For all other values of a the function will have an asymptote at
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Answer A |
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80. |
Answer B |
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| 81. 
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Answer B |
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| 82. 
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Answer B |
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| 83. 
The first three terms are:
From the graph we can see that the maximum value is at (.3,.14463) |
Answer C |
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84.
The series converges for -2<x+2<1 or -3<x<-1 |
Answer B |
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| 85.
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Answer C |
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| 86. Using the function x+2y=8 and solving for y:
This is the diameter
of the semicircle, so the radius is
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Answer C |
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| 87.
Solving for the zero:
Therefore the place where the slope is 1 is at x=.2367329.
The tangent line then is y=1(x-.2367329)+.1152256 or y=x-0.122 |
Answer D |
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| 88. 
f or g' is first positive, then zero, then negative, then zero.
Two possibilities A & C but C ends with g' equal to zero so it is better. |
Answer C |
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| 89. 
So we need to know what
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Answer A
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| 90. 
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Answer A |
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91. |
Answer E |
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| 92. 
graphically solved:
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Answer D |
